AshPhys

Calculating acceleration

AshPhys · Revision cheat sheet
AS Level9702 AS Ch.2Chapter 2: Accelerated motionLesson 2.2Sections 2.2

Goal: Use a = (v − u)/t and rearrange it for v, u or t.

01The big picture

For an object with initial velocity uu that reaches final velocity vv after a time tt, the acceleration is the change in velocity divided by the time.

The same equation, rearranged, gives the final velocity: v=u+atv = u + at. To find the time, tt is in the denominator, so swap it with the lone term aa in one step (cross-multiplication): t=(v−u)/at = (v - u)/a.

Initial velocity uu [paraphrase]
The velocity at the start of the time interval.
Final velocity vv [paraphrase]
The velocity at the end of the time interval.

02Key equations

Acceleration
a=v−uta = \frac{v - u}{t}
Final velocity
v=u+atv = u + at
Time (swap t and a)
t=v−uat = \frac{v - u}{a}
Symbols and units
  • uuinitial velocitym s−1\mathrm{m\,s^{-1}}
  • vvfinal velocitym s−1\mathrm{m\,s^{-1}}
  • tttime takens\mathrm{s}

03Sample problems with solutions

Sample 1 · Velocity and time
A car moving at 5.0 m s⁻¹ accelerates uniformly at 2.0 m s⁻². Calculate (a) its velocity after 6.0 s and (b) the time it takes to reach 25 m s⁻¹.

  1. (a) Final velocity:

    v=u+at=5.0+2.0×6.0=17 m s−1v = u + at = 5.0 + 2.0 \times 6.0 = 17\ \mathrm{m\,s^{-1}}
  2. (b) tt is in the denominator: swap tt and aa.

    t=v−ua=25−5.02.0=10 st = \frac{v - u}{a} = \frac{25 - 5.0}{2.0} = 10\ \mathrm{s}
Answer: (a) 17 m s⁻¹ (b) 10 s
Unit check: m s−1m s−2=s ✓\frac{\mathrm{m\,s^{-1}}}{\mathrm{m\,s^{-2}}} = \mathrm{s}\ \checkmark

04Practice problems

  1. P1
    A train slows from 20 m s⁻¹ to 8.0 m s⁻¹ in 6.0 s. Calculate its acceleration.
    Final answer−2.0 m s⁻²
    Answer: −2.0 m s⁻²
  2. P2
    A stone falls from rest with a=9.81a = 9.81 m s⁻². Find its velocity after 1.5 s.
    Final answer14.7 m s⁻¹ (15 m s⁻¹)
    Answer: 14.7 m s⁻¹ (15 m s⁻¹)
  3. P3
    A plane needs 75 m s⁻¹ to take off and accelerates from rest at 2.5 m s⁻². How long does it take?
    Final answer30 s
    Answer: 30 s
  4. P4
    A cyclist at 6.0 m s⁻¹ decelerates at 0.80 m s⁻². How long until they stop?
    Final answer7.5 s
    Answer: 7.5 s

05Other useful information

Common mistakes

  • ✗ Wrong: Use v−uv - u the wrong way round.

    ✓ Right: Always final minus initial; a negative answer means slowing down.

  • ✗ Wrong: Use a=+0.80a = +0.80 m s⁻² for a deceleration.

    ✓ Right: Use a=−0.80a = -0.80 m s⁻², or the time comes out negative.

Exam tips

  • List uu, vv, aa, tt with units before you substitute.

What the syllabus asks

  • 9702 topic 2: define and use acceleration. Coursebook 2.2.

Explore: Practice questions for this lesson