Calculating acceleration
Goal: Use a = (v − u)/t and rearrange it for v, u or t.
01The big picture
For an object with initial velocity that reaches final velocity after a time , the acceleration is the change in velocity divided by the time.
The same equation, rearranged, gives the final velocity: . To find the time, is in the denominator, so swap it with the lone term in one step (cross-multiplication): .
- Initial velocity [paraphrase]
- The velocity at the start of the time interval.
- Final velocity [paraphrase]
- The velocity at the end of the time interval.
02Key equations
- initial velocity
- final velocity
- time taken
03Sample problems with solutions
Sample 1 · Velocity and time
A car moving at 5.0 m s⁻¹ accelerates uniformly at 2.0 m s⁻². Calculate (a) its velocity after 6.0 s and (b) the time it takes to reach 25 m s⁻¹.
(a) Final velocity:
(b) is in the denominator: swap and .
04Practice problems
- P1A train slows from 20 m s⁻¹ to 8.0 m s⁻¹ in 6.0 s. Calculate its acceleration.
Final answer
−2.0 m s⁻²Answer: −2.0 m s⁻² - P2A stone falls from rest with m s⁻². Find its velocity after 1.5 s.
Final answer
14.7 m s⁻¹ (15 m s⁻¹)Answer: 14.7 m s⁻¹ (15 m s⁻¹) - P3A plane needs 75 m s⁻¹ to take off and accelerates from rest at 2.5 m s⁻². How long does it take?
Final answer
30 sAnswer: 30 s - P4A cyclist at 6.0 m s⁻¹ decelerates at 0.80 m s⁻². How long until they stop?
Final answer
7.5 sAnswer: 7.5 s
05Other useful information
Common mistakes
✗ Wrong: Use the wrong way round.
✓ Right: Always final minus initial; a negative answer means slowing down.
✗ Wrong: Use m s⁻² for a deceleration.
✓ Right: Use m s⁻², or the time comes out negative.
Exam tips
- List , , , with units before you substitute.
What the syllabus asks
- 9702 topic 2: define and use acceleration. Coursebook 2.2.
Explore: Practice questions for this lesson
